Here is the program for transpose of matrix in C.
We first read a matrix of size mxn and then find its transpose by just interchanging the rows and columns i.e. rows become columns and columns become rows.
Transpose of Matrix in C
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 |
#include<stdio.h> int main() { int a[5][5],i,j,m,n; printf("How many rows?"); scanf("%d",&n); printf("How many columns?"); scanf("%d",&m); printf("\nEnter the matrix:\n"); for(i=0;i<m;++i) for(j=0;j<n;++j) scanf("%d",&a[i][j]); printf("\nTranspose of given matrix:\n"); for(i=0;i<m;++i) { for(j=0;j<n;++j) printf("%d ",a[j][i]); printf("\n"); } return 0; } |
Output
How many rows?3
How many columns?3
Enter the matrix:
1 2 3
4 5 6
7 8 9
Transpose of given matrix:
1 4 7
2 5 8
3 6 9