Here you will get simple C++ program to find roots of quadratic equation ax^{2}+bx+c=0.

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#include<iostream> #include<math.h> //to calculate square root using namespace std; int main() { float root1,root2,a,b,c,d,imaginaryPart,realPart; cout<<"Quadratic Equation is ax^2+bx+c=0"; cout<<"\nEnter values of a,b and c:"; cin>>a>>b>>c; d=(b*b)-(4*a*c); if(d>0) { cout<<"\nTwo real and distinct roots"; root1=(-b+sqrt(d))/(2*a); root2=(-b-sqrt(d))/(2*a); cout<<"\nRoots are "<<root1<<" and "<<root2; } else if(d==0) { cout<<"\nTwo real and equal roots"; root1=root2=-b/(2*a); cout<<"\nRoots are "<<root1<<" and "<<root2; } else{ cout<<"\nRoots are complex and imaginary"; realPart = -b/(2*a); imaginaryPart = sqrt(-d)/(2*a); cout<<"\nRoots are "<<realPart<<"+"<<imaginaryPart<<"i and "<<realPart<<"-"<<imaginaryPart<<"i"; } return 0; } |

**Output**

*Quadratic Equation is ax^2+bx+c=0*

*Enter values of a,b and c:3*

*4*

*1*

*Two real and distinct roots*

*Roots are -0.333333 and -1*

genyhow to write the program of complex root?

Bruce Waynenice !

K.M.S.PRAVEENHOW TO WRITE A PROGRAM FOR MEMORY GAME ; PLEASE HELP TO DO IT EASILY !!!!!!!!!!!

AnantThe first two conditions, where d>0 or d=0 are same. In the third condition, that is d<0, do the following:

cout<<"Roots are complex and distinct";

int i;

root1= (-b +sqrt(-d)i)/(2*a);

root2= (-b – sqrt(-d)i)/(2*a);

cout<<"Roots are "<<root1<<" and "<<root2<<endl;

EmmanuelHow do I make a switch statement for the program to solve any quadratic equation.