Permutation of String in C and C++

Here you will get program for permutation of string in C and C++.

Permutation means all possible arrangements of given set of numbers or characters. For a string with n characters can have total n! arrangements. Take below example.

Permutation of String in C and C++

Here we are using backtracking method to find the permutation of a string. Watch below video to understand how to do this.

Below I have shared the code to implement this method in C and C++.

Program for Permutation of String in C

#include <stdio.h>
#include <string.h>
 
void swap(char *x, char *y)
{
    char temp;
    temp = *x;
    *x = *y;
    *y = temp;
}
 
void permutation(char *a, int l, int r)
{
   int i;
   
   if (l == r)
     printf("%s\n", a);
   else
   {
       for (i = l; i <= r; i++)
       {
          swap((a+l), (a+i));
          permutation(a, l+1, r);
          swap((a+l), (a+i));
       }
   }
}
 
int main()
{
    char string[20];
    int n;
    
    printf("Enter a string: ");
    scanf("%s", string);
    
	n = strlen(string);
    permutation(string, 0, n-1);
    
	return 0;
}

Output

Enter a string: abc
abc
acb
bac
bca
cba
cab

Program for Permutation of String in C++

#include <iostream>
#include <string.h>

using namespace std;

void swap(char *x, char *y)
{
    char temp;
    temp = *x;
    *x = *y;
    *y = temp;
}
 
void permutation(char *a, int l, int r)
{
   int i;
   
   if (l == r)
     cout << a << "\n";
   else
   {
       for (i = l; i <= r; i++)
       {
          swap((a+l), (a+i));
          permutation(a, l+1, r);
          swap((a+l), (a+i));
       }
   }
}
 
int main()
{
    char string[20];
    int n;
    
    cout << "Enter a string: ";
    cin >> string;
    
	n = strlen(string);
    permutation(string, 0, n-1);
    
	return 0;
}

Comment below if you have doubts or found any information incorrect in above tutorial.

Source: http://www.geeksforgeeks.org/write-a-c-program-to-print-all-permutations-of-a-given-string/

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