The object oriented programming has been developed with a view to overcome the drawbacks of conventional programming approaches. The OOP approach is based on certain concepts that help it attain its goal of overcoming the drawbacks of shortcomings of conventional programming approaches. These general concepts of OOP are given below: Also Read: How to write and
Basic concepts of OOP Read More »
#include<stdio.h> #include<conio.h> void main() { int i,n,x,large=0; clrscr(); //to clear the screen printf(“How many numbers?”); scanf(“%d”,&n); for(i=0;i<n;++i) { printf(“nEnter number %d:”,i+1); scanf(“%d”,&x); if(x>large) large=x; } printf(“nnThe largest number is %d”,large); getch(); //to stop the screen }
C program to find largest number of a list of numbers entered through keyboard Read More »
#include<iostream.h>#include<conio.h> void main(){ clrscr(); //to clear the screen int i,n,x,large=0; cout<<“How many numbers?”; cin>>n; for(i=0;i<n;++i) { cout<<“nEnter number “<<i+1<<“:”; cin>>x; if(x>large) large=x; } cout<<“nnThe largest number is “<<large; getch();}
C++ program to find largest number of a list of numbers entered through keyboard Read More »
#include<stdio.h> #include<conio.h> void main() { int x,y,z; clrscr(); //to clear the screen printf(“XtYtZtXY+Z”); for(x=0;x<=1;++x) for(y=0;y<=1;++y) for(z=0;z<=1;++z) { if(x*y+z==2) printf(“nn%dt%dt%dt1”,x,y,z); else printf(“nn%dt%dt%dt%d”,x,y,z,x*y+z); } getch(); //to stop the screen }
C program to print the truth table for XY+Z Read More »
#include<iostream.h> #include<conio.h> void main() { clrscr(); //to clear the screen int i,n,x,sum=0; cout<<“How many numbers?”; cin>>n; for(i=1;i<=n;++i) { cout<<“nEnter number “<<i<<“: “; cin>>x; sum+=x; } x=sum/n; cout<<“nnAverage=”<<x; getch(); //to stop the screen }
C++ program to find average of list of numbers entered through keyboard Read More »
#include<stdio.h> #include<conio.h> void main() { int i,j,k,n; clrscr(); //to clear the screen printf(“How many lines:”); scanf(“%d”,&n); n*=2; printf(“n”); for(i=1;i<n;i+=2) { for(j=n-1;j>i;j-=2) printf(” “); for(k=1;k<=i;++k) { if(i==n-1) printf(“*”); else if(k==1||k==i) printf(“*”); else printf(” “); } printf(“n”); } getch(); //to stop the screen; }
C program to produce the following design using *'s Read More »
#include<stdio.h> #include<conio.h> void main() { int i,j,k,n; clrscr(); //to clear the screen printf(“How many lines?”); scanf(“%d”,&n); n*=2; printf(“n”); for(i=0;i<n;i+=2) { for(j=1;j<i;j+=2) printf(” “); for(k=n-1;k>i;–k) printf(“*”); printf(“n”); } getch(); //to stop the screen }
C program to produce the following design using *'s Read More »
#include<stdio.h> #include<conio.h> void main() { int i,j,n; char ch=’A’; clrscr(); //to clear the screen printf(“How many lines?”); scanf(“%d”,&n); for(i=0;i<n;++i) { for(j=0;j<=i;++j) printf(“%c”,ch+j); printf(“n”); } getch(); //to stop the screen }
C program to produce the folowing design using *'s Read More »
