C++ Program to perform all arithmetic calculation using switch case

#include<iostream.h>
#include<conio.h>

void main()
{
clrscr();
float a,b,res;
int ch,q;
cout<<“Arithmetic Operatios”;
cout<<“nn1.Additionn2.Subtractionn3.Multiplicationn4.Divisionn5.Mode”;
cout<<“n  Enter your choice:”;
cin>>ch;

switch(ch)
{
case 1:
{
cout<<“nnEnter two variables:”;
cin>>a>>b;
res=a+b;
cout<<“n  Result=”<<res;
}
break;

case 2:
{
cout<<“nnEnter two variables:”;
cin>>a>>b;
res=a-b;
cout<<“n  Result=”<<res;
}
break;

case 3:
{
cout<<“nnEnter two variables:”;
cin>>a>>b;
res=a*b;
cout<<“n  Result=”<<res;
}
break;

case 4:
{
cout<<“nnEnter two variables:”;
cin>>a>>b;
if(a>=b)
{
res=a/b;
cout<<“n  Result=”<<res;
}
else
cout<<“nnt1st varable should be greater than 2nd.!!!”;
}
break;

case 5:
{
cout<<“nnEnter two variables:”;
cin>>a>>b;
if(a>=b)
{
q=a/b;
res=a-(b*q);
cout<<“n  Result=”<<res;
}
else
cout<<“nnt1st variable should be greater than 2nd..!!!”;
}
break;
}

getch();
}

4 thoughts on “C++ Program to perform all arithmetic calculation using switch case

    1. seemi

      in simple c language prog to make a looped triangle

      #include
      main()
      {
      int i , j ;
      for (i = 1 ; i < = 5 ; i ++)
      {
      for ( j = 1 ; j < = i ; j ++)
      {
      printf ("%d " , j);
      }
      printf ("\n");
      }
      }

      Reply
    2. Mohammead ashik

      Poi pani nokkada no sillly doubts using nested loop we could print in that order. Using nested loop will be the most appropriate way to solve such a problem

      Reply

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