# Python Program to Check Prime Number

Here you will get python program to check prime number.

A number is called prime number if it is only divisible by 1 or itself. For example 2, 3, 5, 7, 11, etc are prime numbers.

Below program takes a number as input and checks it is prime number or not.

## Python Program to Check Prime Number

Output

enter a number: 11
prime number

Comment below if you have any queries related to above python prime number program.

Category: Python Programming A crazy computer and programming lover. He spend most of his time in programming, blogging and helping other programming geeks.

## 24 thoughts on “Python Program to Check Prime Number”

1. Pavan Kumar

Here according to the program else is inside the for loop. When the if condition fails, directly it will print as the number is not prime until checking up to the last value. If I take num=9, then in first iteration (9%2)==0 (false) else statement will be executed. But 9 is not prime right. can u explain me this prgm.

1. Admin Post author

See, this else is not the part of if. In python for loop is little different from other languages like C and C++. In python we can use a else statement with for loop. After the loop ends, else statement is executed. In case break is used somewhere in loop then else is not executed. The program is correct and works fine, just try to run it.

You can learn about for loop in python here https://www.programiz.com/python-programming/for-loop

1. Vanshika

No it is itterating program is wrong

2. H

you are foolish

1. Kritika

You are foolish , just go and run it you will come to know that its correct and if it would be wrong too just have etiquettes to say it wrong . This is not the way to abuse anyone , any human can commit mistakes and after all , he is only helping us . JUST BEHAVE PROPERLY.

3. Amitav

if we are checking with the number 2, this condition becomes true ( if num % i == 0:)
2%2==0. Then why it is going to the else statement?

2. Soham

def prime_check(number= ‘Plese enter a valid number’):
for s in range(2,number+1):
if number<=1 or number / s != 0:

print("it's not a prime number")
else:

print("It's a prime number")
return

3. Rahul Deshmukh

Sir I can check as below also.
I am mentioning the logic here only
initialize i to 2
Store the number to be checked at n
now I will check for every i that whether it divides n or not;and the loop will continue till i reaches n
if for any value of i it divides n,n will be non-prime and if no value of i can divide n then n will be prime.

4. kishan

sir ur program gives an error while we entering greater than 10 .this error only occur when we enter prime number ..

5. robin singh

thanks brother , my program doesn’t runs because i doesn’t put the break statement at end of loop.

for i in range(2,30):
j=2
while j<i:
if i%j==0:
j=j+1
break
else:
print("%s it is prime"%(i))
j=j+1
break

6. vamshi

def primes(num):
list=[]
for i in range (2,int(num/2)+1):
if ((num%i)==0):
break
else:
list.append(i)
return list
primes(11)

1. Birendra Budhathoki

It returns a list of primes upto a number n.

def primes_upto(n):
arr = []
for i in range(1, n+1):
if i in [2, 3]:
arr.append(i)
continue
for j in range (2, (i//2) + 1):
if i % j == 0:
break
if j == i//2:
arr.append(i)
return arr

7. Birendra Budhathoki

This program has a small error. This works fine for other inputs except for 4. It says 4 is a prime number which is actually not.

When input is 4, range function is range(2, 2). This returns an empty list. Thus the execution is jumped to else block. And, it prints ‘prime number’.

Hence, it should be range(2, int(n/2) + 1) instead of range(2, int(num/2)).
This corrects the error!

1. Neeraj Mishra Post author

Thanks for pointing out mistake, I have corrected it.

8. Ali

When the chosen number is 2, how does it not print anything from the if statement when 2%2 is 0. I am confused.

1. Bhartendu Kumar

As the function range(2,var) will produce list of numbers from 2 up to var.i.e. 1 less than var. so in the case var=2,
range(2,2) produces EMPTY LIST. And thus 2 never gets break statement.

9. Bhartendu Kumar

1 is not a prime but this program never considered that.

10. Ugyen Tshering

I really like your code because its very simple and easy to understand.

11. Harish

Sir your program is wrong we check 2 is prime or not they give me 2 is not prime number

12. Prasanna

I want given number is palindrome or not program by using if conditions only don’t use while condition to write that program on python

13. Gitreef

#this code prints prime number according to your limit
for j in range (2,limit):
for i in range(2,j):
if j%i == 0 :
break
else:
print(j)
x=int(input(“enter the limit: “))

14. Adi

# taking input from user
number = int(input(“Enter any number: “))

# prime number is always greater than 1
if number > 1:
for i in range(2, number):
if (number % i) == 0:
print(number, “is not a prime number”)
break
else:
print(number, “is a prime number”)

# if the entered number is less than or equal to 1
# then it is not prime number
else:
print(number, “is not a prime number”)

15. ikju

import math
a = int(input(‘enter a positive number’))

def checkprime(num):
for i in range(2,int(math.sqrt(num))):
if(num % i == 0):
print(“not prime”)
break
else:
print(“prime number”)
return “prime”

b = checkprime(a)

16. ch.akhila

sir,if we take the number as 2 then it will display as not prime number,but it is prime .