#include<iostream.h> #include<conio.h> #include<graphics.h> #include<dos.h> void main() { int x=170,i,gdriver=DETECT,gmode; initgraph(&gdriver,&gmode,”c:\tc\bgi”); settextstyle(DEFAULT_FONT,HORIZ_DIR,2); outtextxy(170,180,”LOADING,PLEASE WAIT”); for(i=0;i<300;++i) { delay(30); line(x,200,x,220); x++; } getch(); closegraph(); }
Here you will get C++ matrix multiplication program. What we are doing in this program. Read number of rows and columns for two matrix. Then check if matrix multiplication is possible or not. If not possible then show a message to user otherwise multiply them. Finally display the result. C++ Matrix Multiplication Program #include<iostream> using …
#include<stdio.h>#include<conio.h>#include<math.h>void main(){ int i,n; float x,sum=0; clrscr(); //to clear the screen printf(“x+x^2/2+x^3/3+…..+x^n/n”); printf(“nEnter value of x and n:”); scanf(“%f%d”,&x,&n); for(i=1;i<=n;++i) sum+=pow(x,i)/i; printf(“nsum=%f”,sum); getch(); //to stop the screen}
#include<iostream.h>#include<conio.h>#include<math.h>void main(){ clrscr(); //to clear the screen int i,n; float x,sum=0; cout<<“x+x^2/2+x^3/3+…..+x^n/n”; cout<<“nEnter value of x and n:”; cin>>x>>n; for(i=1;i<=n;++i) sum+=pow(x,i)/i; cout<<“nsum=”<<sum; getch(); //to stop the screen}
#include<stdio.h>#include<conio.h>#include<math.h>void main(){ int i,n; float x,sum=0; clrscr(); //to clear the screen printf(“1+x+x^2+……+x^n”); printf(“nnEnter the value of x and n:”); scanf(“%f%d”,&x,&n); for(i=1;i<=n;++i) sum+=pow(x,i); sum++; printf(“nSum=%f”,sum); getch(); //to stop the screen}
Hello everyone, few days ago one of my blog visitor sent me a mail. He was facing problem to run program from this blog. That’s why I thought that I should write a small guide regarding this. The step by step process is given below by which you can easily run or use any program …
Complete guide to run any program from this blog Read More »
#include<iostream.h>#include<conio.h> void main(){ clrscr(); //to clrscr the screen int i,n; float sum=0,x,a=1; cout<<“1/2+4/5+7/8+……”; cout<<“nnHow many terms(ex: 1,2,3…n)?”; cin>>n; for(i=0;i<n;++i) { x=a/(a+1); sum+=x; a+=3; } cout<<“nSum=”<<sum; getch(); //to stop the screen}
#include<stdio.h>#include<conio.h> void main(){ int i,n,sum=0; clrscr(); //to clear the screen printf(“1^2+3^2+5^2+…..+n^2”); printf(“nnEnter value of n:”); scanf(“%d”,&n); for(i=1;i<=n;i+=2) sum+=i*i; printf(“Sum=%d”,sum); getch(); //to stop the screen}
