# Program for Armstrong Number in C++

Here you will get program for armstrong number in C++.

A number whose sum of digits raised to power n is equal to itself is called armstrong number. Here n is the total digits in the number.

For example, 153 is armstrong number as 153 = 1+ 5+ 33 = 1 + 125 +27.

## Program for Armstrong Number in C++

Output

Enter any number: 7
The given number is an armstrong number

### 15 thoughts on “Program for Armstrong Number in C++”

1. Shreetej Parkar

there is a fault as wen 1%10, x will become 10 and m will be +1000 rather than +1

1. The logic is absolutely correct, 1%10 = 1. You are telling wrong logic. Just run the program, it is working fine.

2. #include
#include
using namespace std;

int cnt(int num){
int c=0;
while(num!=0){
num=num/10;
c++;
}
return c;
}

int chkArm(int base,int pwr){
int result,temp;

while(base!=0){
temp = base%10;
cout << " temp is — " << temp << endl;
result+=pow(temp,pwr);
cout << "result is — "<<result << endl;
base=base/10;
}
return result;
}
int main()
{
int num,c,result;

cout <>num;

c=cnt(num);

cout << "\nYou entered " << c << " digits." <<endl;

result = chkArm(num,c);

cout << "Result is : " << result << endl;
}

Can some one please tell me that is there any problem in my code ? or if is it correct why its not giving the correct result?