This C++ program will find the sum of squares of n natural numbers. Starting from 1, 2, 3, etc are called natural numbers.
For example:
n = 3
Then, Sum = 12 + 22 + 32 = 14
#include<iostream>
using namespace std;
int main()
{
unsigned long n,i,sum=0,d;
cout<<"Enter any number:";
cin>>n;
for(i=1;i<=n;++i)
{
d=i*i;
sum+=d;
}
cout<<"Sum="<<sum;
return 0;
}
Output:
Enter any number: 50
Sum=42925
Very gd I understand very good
The provided code is very useful.will you please provide the same code using do while loop
The code provided was useful in correcting the code i had written. Could you please provide the Algorithm for this program?
Thanks in advance!!
In while loop
Find the sum of square of first N natural numbers
C++ program please send this program?
Please reply
this is very useful thanks