This C++ program will find the sum of square of n natural numbers.

For example:

n = 3

Then, Sum = 14

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#include<iostream> using namespace std; int main() { unsigned long n,i,sum=0,d; cout<<"Enter any number:"; cin>>n; for(i=1;i<=n;++i) { d=i*i; sum+=d; } cout<<"Sum="<<sum; return 0; } |

**Output**

Enter any number: 50

Sum=42925

Very gd I understand very good

The provided code is very useful.will you please provide the same code using do while loop

The code provided was useful in correcting the code i had written. Could you please provide the Algorithm for this program?

Thanks in advance!!

In while loop

Find the sum of square of first N natural numbers

C++ program please send this program?

Please reply

this is very useful thanks