Here you will get program to reverse number in C++.
using namespace std;
cout<<"Enter any number:";
cout<<"The reversed number is "<<rev;
Enter any number:12674
The reversed number is 47621
12 thoughts on “Program to Reverse Number in C++”
what the statement d=n%10 actually means
% is used to get remainder of a number by dividing it by other number. And if we do modulus of number by 10 then the last digit of number is remainder. Means 123%10=3 or 12%10=2. I hope this will make you clear.
d is empty var, when n is suppose 123, n % 10 is takeing underoot of 123(n) by 10 and saving the remainder 3 into d for 1st loop iteration and then so on.
I used this program but it is not working for numbers starting with zero.
001 should give me 100; but it gives me 1
001 is considered as 1. This program is for number reverse not string reverse.
what the statement rev=(rev*10)+d
what the value of rev in this statement
rev is 0 in 1st iteration so its just rev = (0 * 10) + 3;
you can cout <<rev<<" "; below rev that youll see each iteration value of rev;
this was really helpful… thanku.. but I couldn’t find the solution to write a program to enter a number and print the sum of digits.
cout<<"the sum is:"<<sum<<endl;
how will you print the reverse of 001
why when I enter 6000002345 the output is false
your programs having error always
i think u have to check them and then post ur programs………………..
when i see ur program having error i fell veryyy fustrated …………