Here you will get program to reverse number in C++.

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#include<iostream> using namespace std; int main() { long n,rev=0,d; cout<<"Enter any number:"; cin>>n; while(n!=0) { d=n%10; rev=(rev*10)+d; n=n/10; } cout<<"The reversed number is "<<rev; return 0; } |

**Output**

*Enter any number:12674*

*The reversed number is 47621*

Kennedy Ochiengwhat the statement d=n%10 actually means

Neeraj Mishra% is used to get remainder of a number by dividing it by other number. And if we do modulus of number by 10 then the last digit of number is remainder. Means 123%10=3 or 12%10=2. I hope this will make you clear.

Hamzad is empty var, when n is suppose 123, n % 10 is takeing underoot of 123(n) by 10 and saving the remainder 3 into d for 1st loop iteration and then so on.

Varun GudeI used this program but it is not working for numbers starting with zero.

For example,

001 should give me 100; but it gives me 1

Neeraj Mishra001 is considered as 1. This program is for number reverse not string reverse.

aliwhat the statement rev=(rev*10)+d

what the value of rev in this statement

Hamzarev is 0 in 1st iteration so its just rev = (0 * 10) + 3;

you can cout <<rev<<" "; below rev that youll see each iteration value of rev;

anuj srivastavathis was really helpful… thanku.. but I couldn’t find the solution to write a program to enter a number and print the sum of digits.

Nitish varma#include

#include

#include

void main()

{

clrscr();

int n,x,y,sum;

cout<>n;

x=n%10;

y=n/10;

sum=x+y;

cout<<"the sum is:"<<sum<<endl;

getch();

}

ashwanihow will you print the reverse of 001

noor hameedwhy when I enter 6000002345 the output is false

MESAMEyour programs having error always

i think u have to check them and then post ur programs………………..

when i see ur program having error i fell veryyy fustrated …………