Here you will get program to reverse number in C++.
#include<iostream>
using namespace std;
int main()
{
long n,rev=0,d;
cout<<"Enter any number:";
cin>>n;
while(n!=0)
{
d=n%10;
rev=(rev*10)+d;
n=n/10;
}
cout<<"The reversed number is "<<rev;
return 0;
}
Output
Enter any number:12674
The reversed number is 47621
what the statement d=n%10 actually means
% is used to get remainder of a number by dividing it by other number. And if we do modulus of number by 10 then the last digit of number is remainder. Means 123%10=3 or 12%10=2. I hope this will make you clear.
d is empty var, when n is suppose 123, n % 10 is takeing underoot of 123(n) by 10 and saving the remainder 3 into d for 1st loop iteration and then so on.
I used this program but it is not working for numbers starting with zero.
For example,
001 should give me 100; but it gives me 1
001 is considered as 1. This program is for number reverse not string reverse.
what the statement rev=(rev*10)+d
what the value of rev in this statement
rev is 0 in 1st iteration so its just rev = (0 * 10) + 3;
you can cout <<rev<<" "; below rev that youll see each iteration value of rev;
this was really helpful… thanku.. but I couldn’t find the solution to write a program to enter a number and print the sum of digits.
#include
#include
#include
void main()
{
clrscr();
int n,x,y,sum;
cout<>n;
x=n%10;
y=n/10;
sum=x+y;
cout<<"the sum is:"<<sum<<endl;
getch();
}
how will you print the reverse of 001
why when I enter 6000002345 the output is false
your programs having error always
i think u have to check them and then post ur programs………………..
when i see ur program having error i fell veryyy fustrated …………