Program to Reverse Number in C++

Here you will get program to reverse number in C++.


using namespace std;

int main()
	long n,rev=0,d;
	cout<<"Enter any number:";
	cout<<"The reversed number is "<<rev;

	return 0;



Enter any number:12674
The reversed number is 47621

12 thoughts on “Program to Reverse Number in C++”

    1. % is used to get remainder of a number by dividing it by other number. And if we do modulus of number by 10 then the last digit of number is remainder. Means 123%10=3 or 12%10=2. I hope this will make you clear.

    2. d is empty var, when n is suppose 123, n % 10 is takeing underoot of 123(n) by 10 and saving the remainder 3 into d for 1st loop iteration and then so on.

  1. I used this program but it is not working for numbers starting with zero.
    For example,
    001 should give me 100; but it gives me 1

    1. rev is 0 in 1st iteration so its just rev = (0 * 10) + 3;
      you can cout <<rev<<" "; below rev that youll see each iteration value of rev;

  2. anuj srivastava

    this was really helpful… thanku.. but I couldn’t find the solution to write a program to enter a number and print the sum of digits.

    1. #include
      void main()
      int n,x,y,sum;
      cout<<"the sum is:"<<sum<<endl;

  3. your programs having error always
    i think u have to check them and then post ur programs………………..
    when i see ur program having error i fell veryyy fustrated …………

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