C++ program to swap values of two variables using pass by reference method

C++ program to swap values of two variables using pass by reference method

#include<iostream.h>
#include<conio.h>

void main()
{
clrscr();
int a,b;
void swap(int &,int &);
cout<<“Enter two values:”;
cin>>a>>b;

cout<<“nBefor swapping:na=”<<a<<“tb=”<<b;
swap(a,b);
cout<<“nnAfter swapping:na=”<<a<<“tb=”<<b;
getch();
}

void swap(int & x,int & y)
{
int temp;
temp=x;
x=y;
y=temp;
}

6 thoughts on “C++ program to swap values of two variables using pass by reference method”

  1. /* —- Here is the correct program —- */
    #include
    #include

    using namespace std;

    int main()
    {
    system(“cls”);

    int a,b;
    void swap(int &,int &);
    cout<>a>>b;

    cout<<"\nBefor swapping:\na="<<a<<"\tb="<<b;
    swap(a,b);
    cout<<"\n\nAfter swapping:\na="<<a<<"\tb="<<b;
    getch();
    return 0;
    }

    void swap(int & x,int & y)
    {
    int temp;
    temp=x;
    x=y;
    y=temp;
    }

  2. #include
    #include

    void main()
    {

    // clrscr();

    int a,b;
    void swap(int &,int &);
    cout<>a>>b;

    cout<<"nBefor swapping:na="<<a<<"tb="<<b;
    swap(a,b);
    cout<<"nnAfter swapping:na="<<a<<"tb="<<b;
    getch();
    }

    void swap(int & x,int & y)
    {
    int temp;
    temp=x;
    x=y;
    y=temp

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