Series 0, 1, 1, 2, 3, 5, 8, 13, 21 . . . . . . . is a Fibonacci series. In Fibonacci series, each term is the sum of the two preceding terms.

The C and C++ program for Fibonacci series using recursion is given below.

### C Program

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#include<stdio.h> int fibonacci(int n) { if((n==1)||(n==0)) { return(n); } else { return(fibonacci(n-1)+fibonacci(n-2)); } } int main() { int n,i=0; printf("Input the number of terms for Fibonacci Series:"); scanf("%d",&n); printf("\nFibonnaci Series is as follows\n"); while(i<n) { printf("%d ",fibonacci(i)); i++; } return 0; } |

### C++ Program

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#include<iostream> using namespace std; int fibonacci(int n) { if((n==1)||(n==0)) { return(n); } else { return(fibonacci(n-1)+fibonacci(n-2)); } } int main() { int n,i=0; cout<<"Input the number of terms for Fibonacci Series:"; cin>>n; cout<<"\nFibonacci Series is as follows\n"; while(i<n) { cout<<" "<<fibonacci(i); i++; } return 0; } |

**Output:**

i guess 0 should not have been a part of the series….

so in the function u should have used return fibbonacci(n)+fibbonacci(n-1)

please correct me if i am wrong

For not getting 0 in the output,

i can be initialized as 1 instead of 0 : int i=1;

The while statement needs to be, while(i <= n)(line 24), and (int i = 0) needs to be initialized at 1(line 19), not at 0. Changing this will result in the proper value for any fibonacci(n). As is right now, it is giving you the value at fibonacci(n-1), hence the reason fibonacci(8) yields a value of 13.

Can someone help me with this, write a recursive program to implement the Fibonacci series from 0 to 21.

this is very helpful

thanks

so nice ans

i relly appreciet you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

i need to get the output as, if i enter 15 as input then i should get the answer as 0,1,1,2,3,5,8,13.so, where should i have to change the code?

hi. if we want just the last number of this, what should we do ?

we give : 3

we get : 2

Give me please more and more information about fibonacci. I want to learn C++ very well

i dont know programming