The popularity earned by potable computers or laptops may decline some day as most of their users use them unaware of the consequences of using them wherever they go. Most of them use these sophisticated devices even while enjoying a cup of coffee or other eatables and the residues of the things you eat near …
How to Clean Laptop Parts with Simple Household Products Read More »
Also Read: C++ program to swap two numbers using macros Also Read: C++ Program to find cube of a number using function #include<iostream.h> #include<conio.h> #define CUBE(x) (x*x*x) void main() { clrscr(); int n,cube; cout<<“Enter a number:”; cin>>n; cube=CUBE(n); cout<<“Cube=”<<cube; getch(); }
Hello friends, this is a simple program to create a digital stopwatch. I am sure that even a beginner can understand it very easily. I have written this in c++, so to use it c just change all cout statements with corresponding printf statements. I hope you understand what i want to say. If you …
#include<stdio.h> #include<conio.h> void main() { int i,words=1; char str[100]; clrscr(); printf(“Enter a string:”); gets(str); for(i=0;str[i]!=’’;++i) if(str[i]==’ ‘) words++; printf(“No. of words are %d”,words); getch(); }
In this article I am going to tell you the easiest way to create your own header files in programming languages like C and C++. For this you do not have to be an expert. This can be done by anyone who has just started learning programming languages. Ok! Before starting the process let me …
#include<iostream.h> #include<conio.h> void main() { clrscr(); int *a,*b,*temp; cout<<“Enter value of a and b:”; cin>>*a>>*b; temp=a; a=b; b=temp; cout<<“nAfter swapingna=”<<*a<<“nb=”<<*b; getch(); }
#include<iostream.h> #include<conio.h> #include<math.h> void main() { clrscr(); double sum=0,a; int n,i; cout<<“1+1/2^2+1/3^3+…..+1/n^n”; cout<<“nEnter value of n:”; cin>>n; for(i=1;i<=n;++i) { a=1/pow(i,i); sum+=a; } cout<<“Sum=”<<sum; getch(); }
#include<stdio.h> #include<conio.h> void main() { int i,j,k,n,a,b; clrscr(); printf(“How many lines?”); scanf(“%d”,&n); n=n*2; for(i=1;i<n;i+=2) { for(j=n-1;j>i;j-=2) printf(” “); for(k=1;k<=(i/2)+1;++k) printf(“%d”,k); for(k=i/2;k>=1;–k) printf(“%d”,k); printf(“n”); } getch(); }
